[3log2×4log27+3log81/2log8-2log4]²=

Kelas 10 Matematika
Bab Logaritma

^ = pangkat

((³log 2 . ⁴log 27 + ³log 81)/(²log 8 - ²log 4))²
= ((⁴log 2 . ³log 27) / (²log (8/4))²
= ((1/2 . ³log 3³) / (²log 2))²
= ((1/2 . 3 . ³log 3) / 1)²
= (3/2)²
= 9/4

LogAritMa

[³log 2 × ⁴log27 + ³log 81) / ²log 8 - ²log 4]²
= (³log 2 × 3/2 . ²log 3 + ³log 3⁴) / (²log (8/4))²
= ((3/2 + 4) / 1)²
= (11/2)²
= 121/4
= 30 1/4