Matematika

Pertanyaan

Nilali lim x-2 (2x²-x-10/x²+6x+8)

2 Jawaban

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  • [tex]\displaystyle \lim_{x\to2}\frac{2x^2-x-10}{x^2+6x+8}=\frac{2(2)^2-2-10}{2^2+6(2)+8}\\\lim_{x\to2}\frac{2x^2-x-10}{x^2+6x+8}=\frac{8-2-10}{4+12+8}\\\lim_{x\to2}\frac{2x^2-x-10}{x^2+6x+8}=\frac{-4}{24}\\\boxed{\boxed{\lim_{x\to2}\frac{2x^2-x-10}{x^2+6x+8}=-\frac{1}{6}}}[/tex]

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