tentukan himpunan penyelesaian dari [x-3]={2x+5] dengan mengkuadratkan

Kelas 10 Matematika
Bab Nilai Mutlak

|x - 3| = |2x + 5|
(x - 3)² = (2x + 5)²
(x - 3)² - (2x + 5)² = 0
(x - 3 + 2x + 5) (x - 3 - 2x - 5) = 0
(3x + 2) (-x - 8) = 0
3x + 2 = 0
3x = -2
x = -2/3

-x - 8 = 0
-x = 8
x = -8

HP = { -8, -2/3 }

[x - 3] = [2x + 5]
(x - 3)² = (2x + 5)²
(x - 3)² - (2x + 5)² = 0
x²-6x+9-4x²-20x-25 = 0
-3x²-26x-16= 0
(-x-8) (3x+2) = 0

-x - 8 = 0
-x = 8
x = -8

3x+2 = 0
3x = -2
x = -2/3

HP = { -2/3, -8 }