Matematika

Pertanyaan

tolong pake caranya ya, no 2 sama 3 maksih :)))
tolong pake caranya ya, no 2 sama 3 maksih :)))

2 Jawaban

  • jawab

    x+ 11 = 2x- 27 ( bersebrangan)

    x - 2x = -27 - 11
    -x = - 38
    x = 38

    <AOR = 180 - (x + 11)
    = 180 - (38 +11)
    = 180 - 49
    = 131

    2)

    sudut jam 07. 20 
    p = 7(30 ) + 1/2 (20)
    = 210 + 10
    = 220

    q = 20x 6 = 120

    sudut jam = p - q =  220 -120 = 100
  • 2. Nilai x = 103,5
    jadi, 180°- (x+11)°
    180° - (103,5+11)°
    180° - 114,5°
    = 65,5°
    jadi, ∆AOR = 65,5°

    3. 00.00 - 03.00(siku² = 90°)
    5 menit = 90° : 3
    5 menit = 30°
    1 menit = 6°
    07.00 = 210°
    20menit = 120°
    07.20 = 210°+120°
    07.20 = 330°