tentukan persamaan garis yang bergradien 2 1/3 jika melalui titik (6,3)

y -y₁ = m(x -x₁)
y -3 = 7/3(x -6)
y -3 = 7/3 x -14
                            x3
3y -9 = 2x -42
3y = 2x -42 +9
 3y = 2x -33
Maaf klo slh.

m = 2 1/3, ttk (6,3 )
jwb !
persamaan
y - y1 = m ( x - x1 )
y - 3   = 2 1/3 ( x - 6 )
y - 3   = 7/3 (x - 6 )
----------------------------- × 3
3 (y - 3 )= 7 ( x - 6 )
3y - 9 = 7x - 42
     3y = 7x - 42 + 9
     3y = 7x - 33