Matematika

Pertanyaan

d. ∫ Sin √3x / √3x dx
e. ∫ cos (2x) √3x dx

1 Jawaban

  • Materi : Integral Trigonometri
    Kelas : XII

    d.) Int (sin √3x / √3x) dx
    = int (sin (3x)^1/2 / 3x^1/2 dx
    = int (sin ((3)^1/2 × (x)^1/2) / ((3)^1/2 × (x)^1/2) dx
    = 1/3^1/2 int (sin ((3)^1/2 × (x)^1/2) / ((x)^1/2)
    = √3/3 × int (2sin ((3)^1/2 × (x)^1/2) / (3)^1/2
    = √3/3 × 2/3^1/2 int sin ((3)^1/2 x (x)^1/2)
    = 2/3 (-cos (3)^1/2 × (x)^1/2)
    = - 2/3 cos √3x + c → Merupakan nilai integralnya

    Semoga membantu...

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