Tolong.....................

jawab


1)  pangkat 6
bilangan pascal = 1,6,15, 20,15,6,1

(x² + 1/2 y)⁶ = 

= 1 (x²)⁶ + 6 (x²)⁵(1/2 y) + 15(x²)⁴ (1/2 y)² + 20 (x²)³ (1/2 y)³+ 15(x²)²(1/2 y)⁴ + 6(x²)(1/2 y)⁵ + 1 (1/2 y)⁶

= x¹² + 3 x¹⁰ y + 15/4 x⁶y² + 20/8 x¹⁰ y³ + 15/16 x⁴y⁴ + 6/32 x²y⁵+ 1/32 y⁶


2) pangkat 4 , bilangan pascal ke 4 = 1. 4. 6. 4 . 1

(x ^1/2 + 2y ^1/3)⁴ = 

= 1 (x^(1/2))⁴  + 4 (x^(1/2))³ (2y^(1/3)) + 6 (x^(1/2))² ( 2y^(1/3))² + 4(x^(1/2))(2y^(1/3))³ + 1 (2y^(1/3))⁴

= x² + 8 x^(3/2). y^(1/3) + 24 x^(1) y^(2/3) + 32 x^(1/2) y + 16 y^(3/4)