perhatikan gambar berikut ...

diket :
E = 12 v
r = 1 ohm
R1= 3 ohm
R2 = 2 ohm
t = 1 s
seri
dit : Energi pd R2
jwb :
# Total hambatan luar
Rs = R1+R2
Rs = 3+ 2
Rs = 5 ohm
#Arus rangkaian
I = E / r +Rs
I = 12 / 1+5
I = 12 /6
I = 2 A
# Energi pd R2 ( W2 )
W2 = I^2 . R2 . t
W2 = 2^2 . 2 . 1
W2 = 4 . 2 . 1
W2 = 8 joule
jadi jawab yg ( c )