1) 5log3 = m, dan 3log2 = n, maka 6log75 = 2) 3log√5 . 5log9 + 2log27 . 3log1/4 = buat caranya yaa. nomor yang bisa aja dulu thamks

untuk nomor 1 dulu, semoga membantu

Kelas 10 Matematika
Bab Logaritma

^ = pangkat

1] ^6log 75
= (^3log 75)/(^3log 6)
= (^3log (25 . 3))/(^3log (3 . 2))
= (^3log 25 + ^3log 3) / (^3log 3 + ^3log 2)
= (^3log 5² + 1) / (1 + n)
= (2/m + 1)/(n + 1)
= (2 + m)/(mn + m)

2] ^3log √5 . ^5log 9 + ²log 27 . ^3log (1/4)
= ^5log 5^(1/2) . ^3log 3² + ^3log 3^3 . ²log 2^(-2)
= (1/2) . ^5log 5 . 2 . ^3log 3 + 3 . ^3log 3 . (-2) . ²log 2
= 1/2 . 2 + 3 . (-2)
= 1 - 6
= -5