bantu nomor 21 dan 22 mke cara dan rumus yg jelas

21.
[tex] \frac{3}{4}( \pi\times {r}^{2} ) \\ \\ \frac{3}{4} ( \frac{22}{7} \times {7}^{2} ) \\ = \frac{3}{4} (154) \\ = 115.5 {cm}^{2} [/tex]
22.
[tex]( \frac{1}{2} (\pi \times {r}^{2} ) ) + (a \: \times \: t) \\ = ( \frac{1}{2} ( \frac{22}{7} \times {7}^{2} )) + (14 \times 6) \\ = ( \frac{1}{2} (154)) + 84 \\ = 77 + 84 = 161 {cm}^{2} [/tex]

21.luas lingkaran=
3/4×22/7×7×7=115,5
22.bangun 1=1/2×22/7×7×7=77
bangun 2=14×6:2=42
luas bangun gabungan= bangun 1 + bangun 2
= 77+ 42=119
maaf kalau salah