tolong pake cara yaaa

Materi : Eksponensial Dasar
Kelas : X

[tex] \frac{ {3}^{ - 2} . {2}^{ - 3} }{ {6}^{ - 2} } = \frac{ \frac{1}{ {3}^{2}} . \frac{1}{ {2}^{3} } }{ {6}^{ - 2} } = \frac{ \frac{1}{9}. \frac{1}{8} }{ {6}^{ - 2} } = \frac{ \frac{8 + 9}{72} }{ {6}^{ - 2} } = \frac{ \frac{17}{72} }{ {6}^{ - 2} } \\ = \frac{17 \times {6}^{2} }{72} = \frac{17 \times 36}{72} = \frac{612}{72} = \frac{17}{2} \\ opsi \: a \\ \\ semoga \: membantu...[/tex]