Tolong caranya gimana jalannya ????

smoga membantush_!

jwbnny ad dipict

[tex] \sqrt{3,6}=a [/tex] dan [tex] \sqrt{36} = b[/tex], maka
[tex] \sqrt{3,6} = a \\ \sqrt{ \frac{36}{10} } = a \\ \frac{ \sqrt{36} }{ \sqrt{10} } = a \\ \frac{b}{ \sqrt{10} } = a \\ \frac{b}{a} = \sqrt{10} [/tex]

a. [tex] \sqrt{360} = \sqrt{36.10} = \sqrt{36} \sqrt{10} = b. \frac{b}{a} = \frac{ b^{2} }{a} [/tex]
b. [tex] \sqrt{3600} = \sqrt{36.100} = \sqrt{36} \sqrt{100} = 10b[/tex]
c. [tex] \sqrt{0,36} = \sqrt{ \frac{36}{100} } = \frac{ \sqrt{36} }{ \sqrt{100} } = \frac{b}{10} [/tex]
d. [tex] \sqrt{0,036} = \sqrt{ \frac{36}{1000} } = \frac{ \sqrt{36} }{ \sqrt{1000}} = \frac{ \sqrt{36} }{ \sqrt{100.10} } = \frac{ \sqrt{36} }{ \sqrt{100} \sqrt{10} } = \frac{b}{10 \frac{b}{a} } = \frac{1}{ \frac{10}{a} } = \frac{a}{10} [/tex]