tolong bantu jawab ya

jawab

misal
u  = x - 2 --> du = dx
x = u+ 2

batas integral dalam u
x = 2 --> u = 0
x = 3 --> u = 1

15 ₂³∫ x √(x -2) dx = 15 ₀¹∫(u+2)(u)^(1/2) du

= 15 ₀¹∫ u^(3/2) + 2u^(1/2)  du

= 15 [ 5/2 u ^(5/2) + 2 (3/2) u^(3/2)]¹₀

= 15[ (5/2 (1) + 3 (1)]

= 15  (5/2 + 3)
= 82 ¹/₂