tolong dibantu jawab ya, soal ada di pict

jawab

π/6 
∫  3 cos x  - 2  dx
0

=  3 sin x - 2x ](π/6...0)

= 3 { sin π/6 - sin 0) - 2 (π/6 - 0)
= 3  (sin  30 - sin 0)  - 1/3 π
= 3 (1/2 - 0)  - 1/3 π
= 3/2 - 1/3 π