Soal no.3 ditanya x Soal no.1 ditanya x dan y Tolong dgn caranya, aku tandain jd jawaban terbaik klo bener:)

Teorema Phytagoras , Trigonometri

1.]
[tex] \mathrm{x} = \sqrt{2^2 + 1^2 + 1^2} \\
= \sqrt{6} \\
\mathrm{y} = \sqrt{ [\sqrt6]^2 + 1^2} \\
= \sqrt{37} [/tex]

3.]
[tex] \sin 30^o = \frac{DC}{16} \\
\frac12 = \frac{DC}{16} \\
DC = 8 \\
\\
BC = \sqrt{DB^2 - DC^2} \\
BC = \sqrt{16^2 - 8^2} \\
BC = 8 \sqrt3 \\
\\
\sin 45^o = \frac{\mathrm{x}}{8 \sqrt3} \\
\frac{\sqrt2}{2} = \frac{\mathrm{x}}{8 \sqrt3} \\
\mathrm{x} = 4 \sqrt6 [/tex]