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jawab

40.

f(x) = x² + 4x + 1
f⁻¹ (x² + 4x +1) = x
x² + 4x + 1= y
x² + 4x = y-1
(x+2)² = y - 1 + 4
(x + 2) =  √(y+3)
x = - 2 +√(y+3)
f⁻¹ (x) = - 2 + √(x+3)

fog(x) =9x² -54x  + 78
g(x) = f⁻¹ o { fog)(x)
g(x) = -2 + - √(9x ²- 54x +78+3)
g(x) = - 2 +- √(3x - 9)²
g(x) = - 2 +- (3x -9)
g(x) = -2 + 3x - 9 atau g(x) = 3x -11
g(x) = -2 - 3x +9  atau g(x) = - 3x + 7
g(1) =8 --> g(x) = 3x - 11
g(-1) = 3(-1) - 11
g(-1) = -14