Matematika

Pertanyaan

tolong di bantu y kak
tolong di bantu y kak

2 Jawaban

  • Eksponensial

    [tex] a. \ \frac{1}{4t^6} \\
    = \frac14t^{-6} \\

    \\
    b. \ \frac{5}{(a+b)^3} \\
    = 5(a+b)^{-3} \\
    \\
    c. \ \frac{2}{(b^2+ c^3)^3} [/tex]
    = 2(b² + c³)⁻³
  • a

    1
    ___
    4t^6

    1/4t ^ -6

    b.

    5
    ____
    ( a + b ) ^ 3

    5 ( a + b ) ^ -3

    c.

    2
    _____
    ( b^2 + c^3 ) ^3

    2 ( b^2 + c^3 ) ^ - 3